100=(-32/2500)x^2+x+220

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Solution for 100=(-32/2500)x^2+x+220 equation: 



100=(-32/2500)x^2+x+220

We move all terms to the left:

100-((-32/2500)x^2+x+220)=0



Domain of the equation: 2500)x^2+x+220)!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


-((-32+100*2500)x^2+x+220)=0



We calculate terms in parentheses: -((-32+100*2500)x^2+x+220), so:

(-32+100*2500)x^2+x+220

We add all the numbers together, and all the variables

249968x^2+x+220

Back to the equation:

-(249968x^2+x+220)



We get rid of parentheses

-249968x^2-x-220=0

We add all the numbers together, and all the variables

-249968x^2-1x-220=0

a = -249968; b = -1; c = -220;
Δ = b2-4ac
Δ = -12-4·(-249968)·(-220)
Δ = -219971839
Delta is less than zero, so there is no solution for the equation

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